A simple shell sort program that I wrote using C programming language.

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Program Listing

/* shell_sort.c
   Author   : Mr. Jake Rodriguez Pomperada,MAED-IT, MIT
   Tool     : Dev C++ 5.11
   Date     : August 15, 2021   Sunday  4:29 PM
   Websites  : www.jakerpomperada.com and www.jakerpomperada.blogspot.com
   Email    :jakerpomperada@gmail.com
   Location : Bacolod City, Negros Occidental, Philippines
*/

#include <stdio.h>
#include <stdlib.h>

void shellsort(int arr[], int num);

int main()
{
 int items[1000], num=0,min=0,loc=0;
 int c=0, b=0,change=0,j=0,temp=0;
 system("cls");
 printf("\n\n");
 printf("\tShell Sort Program in C");
 printf("\n\n");
 printf("\tHow many items? : ");
 scanf("%d", &num);
 printf("\n\n");
 for (c= 0; c < num; c++) {
    printf("\tEnter item no. %d: ", c+1);
    scanf("%d", &items[c]);
 }
printf("\n\n");
printf("\tOriginal Arrangement of Numbers");
printf("\n\n");
 for ( c = 0 ; c < num ; c++ ) {
   printf("\t%d ",items[c]);
 }
 shellsort(items, num);
 printf("\n\n");
 printf("\tAsceding Order of Numbers");
 printf("\n\n");
 for ( c = 0 ; c < num ; c++ ) {
 printf("\t%d ", items[c]);
 }  
printf("\n\n");
printf("\tEnd of Program");
printf("\n\n");
system("pause");
}

void shellsort(int arr[], int num)
{
    int i, j, k, tmp;
    for (i = num / 2; i > 0; i = i / 2)
    {
        for (j = i; j < num; j++)
        {
            for(k = j - i; k >= 0; k = k - i)
            {
                if (arr[k+i] >= arr[k])
                    break;
                else
                {
                    tmp = arr[k];
                    arr[k] = arr[k+i];
                    arr[k+i] = tmp;
                }
            }
        }
    }
}


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